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Home/ Questions/Q 7052977
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T03:26:55+00:00 2026-05-28T03:26:55+00:00

I have a query which returns 644 rows, grouped by several columns. I need

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I have a query which returns 644 rows, grouped by several columns. I need to get a count of these rows, 644.

This is the query:

SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count]
FROM HeadOffice ho INNER JOIN Properties ON Properties.head_office_code = ho.id
WHERE Somecondition
GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status

Despite trying COUNT(*), wrapping it in another query and removing the GROUP BY, I can’t get ‘644’ back. The closest I’ve come is 644 rows, all containing ‘1’. Is this possible?

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  1. Editorial Team
    Editorial Team
    2026-05-28T03:26:56+00:00Added an answer on May 28, 2026 at 3:26 am

    The easy way to do it is thusly:

    SELECT count(1) as NumRows from
    (SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count]
    FROM HeadOffice ho INNER JOIN Properties ON clients.head_office_code = ho.id
    WHERE Somecondition
    GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status) x
    

    If you want the count plus your columns, use over:

    SELECT 
        count(1) over () as NumRows,
        x.ID,
        x.ho_status,
        x.[sales value],
        x.[property count]
    from
    (SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count]
    FROM HeadOffice ho INNER JOIN Properties ON clients.head_office_code = ho.id
    WHERE Somecondition
    GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status) x
    
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