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Home/ Questions/Q 7547987
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T09:35:50+00:00 2026-05-30T09:35:50+00:00

I have a query which returns a result set which looks like this: A

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I have a query which returns a result set which looks like this:

A   |   B
---------------------
1   |   a
2   |   a
1   |   b
1   |   c
3   |   d

A|B is unique in the results (i.e. there will only ever be one 1|a row)

I need to write two queries based on these results. The first:

given a value for A (say 1), count the number of Bs who only have a single row; with a 1 in the A column.

so in the above data set, id expect to be returned the value 2, because B values b and c only have one row each, where those rows have a 1 in the A column. d would not be counted because it corresponds to a 3 and a would not be returned because it has an additional row with a 2.

Hope that makes sense.

The second query is the opposite to the above.

Given a value for A (say 1) count the number of Bs who have 2 or more rows, where one of the rows has a 1 in the A column.

So in the above data id expect to be returned 1, because the B value a is the only one that has multiple rows, with one of them with a 1 in the A column.

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-30T09:35:52+00:00Added an answer on May 30, 2026 at 9:35 am

    With CTEs and windowed aggregate functions, it could be done like this:

    WITH
      sampledata (A, B) AS (
        SELECT 1, 'a' UNION ALL
        SELECT 2, 'a' UNION ALL
        SELECT 1, 'b' UNION ALL
        SELECT 1, 'c' UNION ALL
        SELECT 3, 'd'
      ),
      counted AS (
        SELECT
          A,
          B,
          COUNT(*) OVER (PARTITION BY B) B_count
        FROM sampledata
      )
    SELECT
      COUNT(*)
    FROM counted
    WHERE A = 1
      AND B_count = 1  /* change to "> 1" to get the other result */
    
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