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Home/ Questions/Q 8887231
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T21:45:20+00:00 2026-06-14T21:45:20+00:00

I have a query which returns the custref having multiple tetranumbers(1 to n mapping)

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I have a query which returns the custref having multiple tetranumbers(1 to n mapping)

select *
  from cdsheader
 where custref in(select custref
                    from(select *
                           from cdsheader h,custandaddr c
                          where h.custref = c.cwdocid
                            and c.addresstype = 'C')
                   group by custref
                  having count(distinct( tetranumber )) > 1) 

count 5144

My objective is to pull the matching address details along with the above result, but I guess I am missing something here.

Something like…

select a.cworderid,a.cwcreated,a.organisationtype,a.custref,a.tetranumber,
       b.buildingname,b.streetname,b.posttown,b.postcode,b.country
  from cdsheader a,custandaddr b
 where custref in (select custref
                     from cdsheader h,custandaddr c
                    where h.custref = c.cwdocid
                      and c.addresstype = 'C')
                    group by custref
                   having count(distinct( tetranumber )) > 1)
 order by a.custref,a.tetranumber,a.cworderid; 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T21:45:22+00:00Added an answer on June 14, 2026 at 9:45 pm

    Rather than scanning your table twice ,create a inline view and fetch the result using analytical function .Please test

    SELECT     inner.cworderid,
               inner.cwcreated,
               inner.organisationtype,
               inner.custref,
               inner.tetranumber,
               inner.buildingname,
               inner.streetname,
               inner.posttown,
               inner.postcode,
               inner.country
    FROM(           
      SELECT   h.cworderid,
               h.cwcreated,
               h.organisationtype,
               h.custref,
               h.tetranumber,
               c.buildingname,
               c.streetname,
               c.posttown,
               c.postcode,
               c.country,
               COUNT(DISTINCT tetranumber) OVER(PARTITION BY h.custref) cnt
        FROM   cdsheader h, custandaddr c
        WHERE  h.custref = c.cwdocid 
           AND c.addresstype = 'C'
          )inner
      WHERE inner.cnt>1 
     ORDER BY inner.custref, inner.tetranumber, inner.cworderid;  
    
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