Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6757605
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T13:40:23+00:00 2026-05-26T13:40:23+00:00

I have a query,and I am having the following error returned however I cannot

  • 0

I have a query,and I am having the following error returned however I cannot find the problem,

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘HAVING DATE_FORMAT(NOW(), ‘%Y’) – DATE_FORMAT(candidates.DOB, ‘%Y’) – (DATE_’ at line 14

this is my query,

SELECT `candidates`.`candidate_id`, 
       `candidates`.`first_name`, 
       `candidates`.`surname`, 
       `candidates`.`DOB`, 
       `candidates`.`gender`, 
       `candidates`.`talent`, 
       `candidates`.`location`, 
       `candidates`.`availability`, 
       DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) 
                   as `age`, 
       `candidate_assets`.`url`, 
       `candidate_assets`.`asset_size` 
FROM `candidates` 
LEFT JOIN `candidate_assets` ON `candidate_assets`.`candidates_candidate_id` = `candidates`.`candidate_id` 
WHERE `candidates`.`availability` = 'yes' 
AND candidates.talent = "presenter" 
AND candidates.gender = "male" 
HAVING DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) <= 39
AND HAVING DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(`candidates`.`DOB`, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(`candidates`.`DOB`, '00-%m-%d')) <=29 
GROUP BY `candidates`.`candidate_id`

what is the problem, I am not an avid user of mySQL

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T13:40:24+00:00Added an answer on May 26, 2026 at 1:40 pm

    Three things I see right away:

    1 – HAVING should only occur once in the query, not twice.
    2 – HAVING should always come after GROUP BY
    3 – HAVING only applies to AGGREGATE FUNCTIONS, not something like a date comparison. If you want a date comparison you should use a WHERE clause.

    There may be more but your query is extremely hard to read in the current “format”. If you need more help, please put at least SOME effort into making your question readable.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Having a problem with the following Query. i have a device table which logs
I have the following query: select column_name, count(column_name) from table group by column_name having
I have written a SQL query that works just fine, but am having a
I'm having difficulty working out how to 'error handle' as such the following SQL.
I'm having some problem with my SQL syntax/escaping variables on my LAMP server. The
Am having some SQL ( SqlCe ) issues I was getting the following error:
I have the following query which returns the following error: An aggregate may not
I have the following SQL Server 2008 query that works for all of my
So im having a problem (obviously). I have the following MySQL table data 7
i'm having problems in executing a query inside php. I have the following query

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.