Question

I have a question about how can I change some files names. The problem is I have this kind of archives, for example:

25614_z.zip
25312_z.zip
25003_z.zip

And I want to create that:

lp_25_614.zip
lp_25_312.zip
lp_25_003.zip

So, I need to automatize this process

lp + 25 (the two first digits) + the number in the 3 4 and 5 position) + dot zip

Is there any way to do it?

EDIT

For example, this would be my condition:

XXXX

if fileNames{k}(3:5) >0 <5 (the interval)= 2
fileNames{k}(3:5)> >5 >10 =10

So, for example:

fileNames{k}(3:5) = 05

after the condition it would be replaced in the rename with= 2

And then I want to add it on the rename name.

newFileName = ['fiche' fileNames{k} (3) 'pd' fileNames{k}(3:5) 'XXX '.tar.gz']; 

Is that possible?

Answer 1

You can use movefile to rename the files:

 myPath = 'C:\myFolder\'; % path to your files

fileNames = {
    '25614_z.zip'
    '25312_z.zip'
    '25003_z.zip'
    }


for k = 1:length(fileNames)
    newFileName = ['lp_' fileNames{k}(1:2) '_' fileNames{k}(3:5) '.zip'];
    % renaming
    movefile([myPath fileNames{k}], [myPath newFileName]); 
end

~edit~
Concerning your edit: yes it is possible to generate the file name different for separate cases. Note that the example below is quite clumsy and should only be used if you have only a small number of different cases.

myPath = 'C:\myFolder\'; % path to your files

fileNames = {
    '25614_z.zip'
    '25312_z.zip'
    '25003_z.zip'
    }


for k = 1:length(fileNames)
    n = num2str(fileNames{k}(3:5));
    if n > 0 && n < 5
        fileName = % put your file name for this case here
    elseif n >= 5 && n < 10
        fileName = % put your file name for this case here
    elseif n >= 10 && n < 20
        fileName = % put your file name for this case here
    end
    % renaming
    movefile([myPath fileNames{k}], [myPath newFileName]);
end