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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:32:09+00:00 2026-05-13T11:32:09+00:00

I have a question about the following code: class MyClass : private boost::noncopyable {

  • 0

I have a question about the following code:

class MyClass : private boost::noncopyable
{
    public:

    MyClass() {}
    virtual ~MyClass() {}
}

class OtherClass : private boost::noncopyable
{
    private:
    MyClass* m_pMyClass;
}

My thoughts are that MyClass cannot be copied using construction or assignment. Using a virtual destructor is needed if I want to support deriving classes from MyClass, which I do not want to support. I do not intend to create pointers to this class and pass them around.

I do not want a Singleton and I cannot see a downside to removing the virtual destructor.

Do I introduce a potential problem if remove the virtual destructor for a noncopyable class? Are there a better practices to handle a class that does not need to be a Singleton, but I only want one instance in another class and not support inheritance?

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:32:09+00:00Added an answer on May 13, 2026 at 11:32 am

    No, the entire point of a virtual destructor is so derived classes can properly destruct polymorphically. If this will never be a base class, you don’t need it to be virtual.

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