Question

i have a question about the function call in the following example:

int main()
{
    int a, b;
    cin  >> a >> b >> endl;
    cout << *f(a,b);
    return 0;
}

So is *f(a,b) a valid function call?

Edit:: sorry for the errors, i fixed them now i’m a little tired

Answer 1

The code at least could be reasonable. For it to work, f must be defined as a function that returns either of two sorts of things: either it returns a pointer, in which case the * dereferences the pointer, so whatever it was pointing at gets sent to standard output. Otherwise, f must return some user-defined type that defines operator * to return something that’s compatible with cout.