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Home/ Questions/Q 8995767
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T23:39:48+00:00 2026-06-15T23:39:48+00:00

I have a question, here’s the code: @interface MyFoo : NSObject { NSString *nameStr;

  • 0

I have a question, here’s the code:

@interface MyFoo : NSObject {
    NSString *nameStr;
}
@end
@implementation MyFoo
- (id)init {
    self = [super init];
    if (self) {
        self->nameStr = [@"some value of the string that is set right into the private ivar" copy];
    }
    return self;
}
@end

The question is: ignoring all the C++ rules, ignoring memory dump vulnerability, why exactly I shouldn’t use such arrow operator syntax?
Is there somewhere in Apple documentation a rule which says that it’s incorrect because in future class may be represented differently than a pointer to a struct in runtime etc. ?

Thanks in advance!

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  1. Editorial Team
    Editorial Team
    2026-06-15T23:39:49+00:00Added an answer on June 15, 2026 at 11:39 pm

    The use of self->someIvar is identical to someIvar. It’s not wrong but it’s not needed either.

    The only time I use the arrow notation is in an implementation of copyWithZone: so I can copy each of the ivars that don’t have properties.

    SomeClass *someCopy = ...
    someCopy->ivar1 = ivar1; // = self->ivar1
    someCopy->ivar2 = ivar2; // = self->ivar2
    

    Where are you seeing anything that says you shouldn’t use such arrow operator syntax?

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