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Home/ Questions/Q 6380233
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T02:14:31+00:00 2026-05-25T02:14:31+00:00

I have a question on ‘call’ in javascript. var humanWithHand = function(){ this.raiseHand =

  • 0

I have a question on ‘call’ in javascript.

var humanWithHand = function(){
    this.raiseHand = function(){
        alert("raise hand");
    }
}

var humanWithFoot = function(){
    this.raiseFoot = function(){
        alert("raise foot");
    }
}

var human = function(){

    humanWithHand.call( this );
    humanWithFoot.call( this );

}

var test = new human();

so..when I use ‘call’ as humanWithHand.call(this), what happens internally?

does humanWithHand variable copies (or points?) its properties and members to human variable’s prototype?

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  1. Editorial Team
    Editorial Team
    2026-05-25T02:14:31+00:00Added an answer on May 25, 2026 at 2:14 am

    .call() sets the this value and then calls the function with the arguments you passed to .call(). You use .call() instead of just calling the function directly when you want to set the this value inside the called function rather than let it be set to whatever javascript would normally set it to.

    .apply() is a sister function. It can also set the this value and it can take arguments in an array so it can be used when you are trying to pass a variable argument list from some other function call or when you’re constructing an argument list programmatically which may have different numbers of arguments depending upon the situation.

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