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Home/ Questions/Q 6356387
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T22:57:01+00:00 2026-05-24T22:57:01+00:00

I have a question regarding efficiency of jQuery filtering. I’ve just written quite a

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I have a question regarding efficiency of jQuery filtering. I’ve just written quite a lengthy expression and I was wondering if jQuery stops filtering if the current number of matches is 0.

passengers.filter('input.FromDate[value="01/09/2011"]')
          .closest('tr')
          .filter('input.ToDate[value="08/09/2011"]')
          .length;

If after the first filter() call the number of matches is 0 will jQuery continue to search the DOM or will it forego the additional calls and just return 0?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T22:57:03+00:00Added an answer on May 24, 2026 at 10:57 pm

    The nice thing about chainable calls with jQuery is that when there are no matches, nothing bad will happen.

    When you call .filter and zero matches have been yielded, you are executing the subsequently chained method calls by definition because they are invoked directly on the returned object (that’s what chaining is).

    When there are no matches, JavaScript will still invoke each subsequently chained method on each returned object. How much wasted processing happens depends on how the specific method has been implemented.

    $.fn.doesItTryToDoStuff = function() {
        alert('called');
    
        // here I could have some wasteful process
        // which could foolishly be executed
        // even when there are no elements
    
    
        return this.each(function() {
           $(this).css("border", "1px solid red"); 
        });
    };
    
    $("input").filter("[value='foo']").doesItTryToDoStuff().doesItTryToDoStuff();
    

    Demo.

    I would expect that most jQuery methods are coded such that nothing drastic happens before the length of the collection has been tested, but you never know.

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