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Home/ Questions/Q 8907963
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T03:03:14+00:00 2026-06-15T03:03:14+00:00

I have a question regarding the deletion from arrays. I have a 3-D numpy

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I have a question regarding the deletion from arrays. I have a 3-D numpy array (coordinates are z,y,x) with an estimated 900^3 size. Only a few values are nonzero, but they have a nontrivial spatial distribution. I want to delete all 2-D slices in that array which have only zeros in it. In other words, I want an array with minimum size which still has all relevant data in it.

My attempt looks like:

    while np.all(a[0]==0):
        a=np.delete(a,0,0)
    while np.all(a[a.shape[0]-1]==0) and a.shape[0]>1:
        a=np.delete(a,-1,0)

and seems to work for the z-direction. How can I do something equal in the other two directions? And is there maybe another way of doing it better?

Another Idea was

tmp=np.delete(tmp,np.all(tmp==0,axis=1),1)

but that one seems to work only from the start and leaves out the zeros at the end.

Is it maybe possible, to rotate an array in 3D space?

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  1. Editorial Team
    Editorial Team
    2026-06-15T03:03:15+00:00Added an answer on June 15, 2026 at 3:03 am

    You can use transpose to rearrange your axes, but it sounds like you might really be looking for a sparse array

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