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Home/ Questions/Q 1025621
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T11:57:19+00:00 2026-05-16T11:57:19+00:00

I have a question regarding the following code: abstract class a { public static

  • 0

I have a question regarding the following code:

abstract class a
{
    public static string x;
}



class b<c> where c : a
{
    public void f()
    {
        c.x=10;
    }
}

This code does not compile. I get an error at the statement c.x=10; . The problem makes it look as if the condition where c:a does not have any effect at all.Can someone please explain why this is an error? Is it not true that x is shared as a static member by all children of a? And is there a way to circumvent this problem?

What I am trying to achieve is this : i have a subclass of a, all of whose objects share a common property and this property has to be set through f() in the generic class b. Is it alright if i replace the statement in question with a.x=10? If not, how is a.x different from c.x (or h.x where h is the subclass of a)?

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  1. Editorial Team
    Editorial Team
    2026-05-16T11:57:20+00:00Added an answer on May 16, 2026 at 11:57 am

    Static members are not inherited, although it’s confusingly possible to access a static member through a derived type. For example, in the following code

    class P
    {
        public static string X;
    }
    
    class Q : P { }
    
    class R : P { }
    

    you can access P.X through P.X or Q.X or R.X but it’s still the same field:

    P.X = "Hello";
    Q.X = "World";
    Console.WriteLine(R.X);  // prints "World"
    

    As you’ve discovered, you can’t do this with generic type parameters. But accessing X though the type parameter doesn’t really make a lot of sense, because all you change is P.X which you write directly without the generic type parameter.


    I’m not really sure what you’re trying to achieve. If you have an abstract class A and want all instances of types that derive from A to have a certain property, you can define this:

    abstract class A
    {
        public abstract string X
        {
            get;
        }
    }
    
    class A1 : A
    {
        public override string X
        {
            get { return "A1"; }
        }
    }
    
    class A2 : A
    {
        public override string X
        {
            get { return "A2"; }
        }
    }
    

    If you want to associate a bit of information with a type (not instance), you can define a static field that is parameterized with a type using a generic class:

    class Info<T>
    {
        public static string X;
    }
    
    Info<A1>.X = "Hello";
    Info<A2>.X = "World";
    
    Console.WriteLine(Info<A1>.X);  // prints "Hello"
    Console.WriteLine(Info<A2>.X);  // prints "World"
    

    What about this?

    abstract class Job
    {
        public abstract string ExePath
        {
            get;
        }
    
        public void Execute(string[] args)
        {
            Console.WriteLine("Executing {0}", this.ExePath);
        }
    }
    
    abstract class Job<T> where T : Job<T>
    {
        public override string ExePath
        {
            get { return JobInfo<T>.ExePath; }
        }
    }
    
    class ConcreteJob1 : Job<ConcreteJob1> { }
    
    class ConcreteJob2 : Job<ConcreteJob1> { }
    
    static class JobInfo<T> where T : Job<T>
    {
        public static string ExePath;
    }
    
    static class JobInfoInitializer
    {
        public static void InitializeExePaths()
        {
            JobInfo<ConcreteJob1>.ExePath = "calc.exe";
            JobInfo<ConcreteJob2>.ExePath = "notepad.exe";
        }
    }
    

    This matches closely the process you describe in your comment. It should work, although it’s not how I would design a configurable Job model.

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