Question

I have a question simple like that: Let user enter some words from keyboard,one word per line until a ‘.’ (period) entered then print out result, for example:

Enter a word: word1
Enter a word: word2
Enter a word: .
You have entered 2 word(s):
word1
word2

OK here my try but when I run it said file has stopped working after let me enter first word

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <string.h>

int main () 
{ 
    char *word[50]; //each word has maximum 49 character
    int i=0, number_of_word;

    do
    {
        printf ("Enter a word: ");
        scanf("%s", &word[i]);
        i++;
    }
    while (word[i][0]!='.');

    number_of_word =i;
    printf ("You entered %d word(s):\n", number_of_word);
    for (i=0; i<number_of_word; i++)
    {
        printf("%s\n", &word[i]);
    }

    return 0;
}

———————————————————————–

EDIT 1:

OK I try this, it worked but I am still looking for best way to declare an unknown size array of character string since I don’t know neither how many word user may enter nor how many letter of each word, in C++ it may called dynamic allocation array, I have no idea how to do it in C

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <string.h>

int main () 
{ 
    char word[20][50]; //array has maximum 20 words, each word maximum 50 character
    int i=0, number_of_word;

    do
    {

        printf ("Enter a word: ");
        scanf("%s", word[i]);
        i++;
    }
    while (word[i-1][0]!='.');

    number_of_word =i-1;
    printf ("You entered %d word(s):\n", number_of_word);
    for (i=0; i<number_of_word; i++)
    {
       printf("Word %d is %s\n", i, word[i]);
    }


    return 0;
}

Answer 1

You are not assigning any memory to store the individual strings, so your program invokes undefined behaviour.

This:

char *word[50];

defines an array of 50 pointers, but no further storage.

And when you do this:

scanf("%s", &word[i]);

you’re writing into the pointer array.