Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 5967365
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T19:56:00+00:00 2026-05-22T19:56:00+00:00

I have a queue problem. Modeling a graph, I’m doing a shortest path algorithm

  • 0

I have a queue problem. Modeling a graph, I’m doing a shortest path algorithm in C++.

In my while (!q.empty()) the front vertex* gets changed when I return to this statement.

Can you figure out why?

int MyMatrix::searchBreadth(MyVertex* from,MyVertex* to)
{
queue<MyVertex*> q;  
path=INFINITY;

from->visit();  
from->setDistance(0);  
q.push(from);  

//here q.front()'s attributes get changed when returning from the for-loop  
while(!q.empty())
{  
    MyVertex* v=q.front();  
    q.pop();  
    int k=v->getDistance();  
    vector<MyVertex> nb=getNeighbours(*v);  
    for(int i=0;i<nb.size();i++)  
    {  
        if(nb[i].getDistance()==INFINITY)
        {  
            nb[i].setDistance(k+1);  
            q.push(&nb[i]);  
        }

        if((nb[i].getName().compare(to->getName())==0)
           && !nb[i].isVisited())
        {
            //path found  
            int j=nb[i].getDistance();  
            if(j<path) path=j;  
        }  

        nb[i].visit();  
     }  
}  
return path;  

}   

here comes getNeighbours()

vector<MyVertex> MyMatrix::getNeighbours(MyVertex &v)
{  
    int index=0;  
    for(int l=0; l<stations.size(); l++ )
    {  
        if(stations[l].getName().compare(v.getName())==0)index=l;  
    }

    vector<MyVertex> out;  
    for(int k=0;k<matrixSize;k++)
    {  
        if(matrix[index][k].getName().compare("null")!=0)
        {  
            out.push_back(matrix[index][k].getTo());  
        }  
    }  

    return out;
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T19:56:01+00:00Added an answer on May 22, 2026 at 7:56 pm

    Your problem is subtle, but related to q.push(&nb[i]). What you’re doing is adding a pointer to a location in a vector, which is not conceptually the same as adding a pointer to a MyVertex object. The vector of neighbors contains the MyVertex objects “by value” (if that helps in your understanding of the problem).

    A look at nb in memory may help:

            0         1                   I
    nb [MyVertex0|MyVertex1|   ...   |MyVertexI]
                 +---------+
                      | (Notice it is NOT pointing to MyVertex1!)
    &nb[1]------------+
    

    When you push &nb[1] you’re pushing the address nb + (1 * sizeof(MyVertex)). nb is declared on the stack, so that address is going to be somewhere on the stack.

    So when your for-loop comes back around, nb gets refreshed (so to speak) and new data is added. However, your queue q contains addresses into nb that are no longer valid!

    Simply put: your queue is referencing a LOCATION in the vector, not the DATA in the vector.

    If you want to keep your method as-is, this means getNeighbors needs to change to return a vector of MyVertex*.


    You should simply edit BreadthFirstSearch to take two MyVertex&, rather than pointers. You would then change q to be a queue<MyVertex>, v to MyVertex, and finally you should change q.push(&nb[i]) to just q.push(nb[i]).

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a Microsoft Message Queue that gets populated with messages. If there is
I have a problem with my program, which is using IPC message queue. Althought
I'm trying to create simply connect with ActiveMQ using JNDI. I have: Queue named
I have a Queue<T> object that I have initialised to a capacity of 2,
I have a Queue object that I need to ensure is thread-safe. Would it
I have a priority queue implementation in C# that I want to add a
I have a list/queue of 200 commands that I need to run in a
I have multiple processes monitoring an MSMQ queue. I want to do multi-step operations
I have one thread that writes results into a Queue. In another thread (GUI),
I have a windows service listening to messages from a queue but the messages

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.