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Home/ Questions/Q 1028091
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T12:20:02+00:00 2026-05-16T12:20:02+00:00

I have a raw audio file captured from a camera in the format u-law

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I have a raw audio file captured from a camera in the format u-law mono 8KHZ (no wav headers). The problem I am having is that when I try to play back the file, I just seem to get bad noise. I have plugged the raw audio through a program called goldwave, and it is able to playback the file perfectly. I am sure I am just missing something simple.

I have been trying to use the waveout functions but with no luck. Do I need to decode the data from u-law first before trying to push it through the waveout functions?

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  1. Editorial Team
    Editorial Team
    2026-05-16T12:20:03+00:00Added an answer on May 16, 2026 at 12:20 pm

    If you’re just using the waveOut functions in the Windows API, the third parameter to waveOutOpen is a pointer to a WAVEFORMATEX structure:

    MMRESULT waveOutOpen(
        LPHWAVEOUT phwo,
        UINT_PTR uDeviceID,
        LPWAVEFORMATEX pwfx,
        DWORD_PTR dwCallback,
        DWORD_PTR dwCallbackInstance,
        DWORD fdwOpen
    );
    

    A WAVEFORMATEX structure lets you specify the format, and Windows should be able to do u-Law without you needing to install anything.

    typedef struct {
      WORD  wFormatTag;
      WORD  nChannels;
      DWORD nSamplesPerSec;
      DWORD nAvgBytesPerSec;
      WORD  nBlockAlign;
      WORD  wBitsPerSample;
      WORD  cbSize;
    }WAVEFORMATEX;
    

    Set wFormatTag to WAVE_FORMAT_MULAW, or 0x0007. Be sure you fill out the other parameters correctly for 1 channel with 8000 samples/sec and 8 bits/sample.

    If that fails, please post the code where you open the audio device and play the file. Or here’s a delphi implementation of u-Law decoding to linear PCM (ulawDecode) so you can decode it yourself:

    http://www.koders.com/delphi/fidEAA58384F59968FEDD0670F6EABF09DF3A5C58A5.aspx?s=algorithm#L19

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