Question

I have a registration form in html and a php code that connects to the database. Now if the registration is successful and is added to the database, how to i alert the user that it is successful with a popup box?

the html code is just a simple form codes so heres the php code:

<?php

if(isset($_POST['submit'])){
    $fname = $_POST['firstname'];
    $lname = $_POST['lastname'];
    $mname = $_POST['middlename'];
    $birthday = $_POST['year'] . '/' . $_POST['month'] . '/' . $_POST['day'];
    $sex = $_POST['sex'];
    $age = $_POST['age'];
    $address = $_POST['address'];
    $telephone = $_POST['telephone'];
    $occupation = $_POST['occupation'];
    $telephone = $_POST['telephone'];
    $cfname = $_POST['contactfirstname'];
    $clname = $_POST['contactlastname'];
    mysql_connect('localhost', 'root', '');
    mysql_select_db('HMIS');

    $query = "INSERT INTO `patientrecords` VALUES('','$lname','$fname','$mname','$birthday','$sex','$address','$telephone','$occupation','$clname','$cfname')";

    if(mysql_query($query)){
        echo "Registered";
    }else{
        echo "Error!". mysql_error();
    }
}

?>

I can do the javascript alert box only when a certain button is clicked. But in the php code you dont need a button.. so.. how do you do it?

Answer 1

Try this, it should work

if(success)
{
   echo "<script type=\"text/javascript\">".
        "alert('success');".
        "</script>";
}