Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8996379
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T23:44:49+00:00 2026-06-15T23:44:49+00:00

I have a regular expression |^(/[a-z]{2})?/?(php)/([-a-z0-9]+)/?/?$| Which match /php/anything . Now I want a

  • 0

I have a regular expression

|^(/[a-z]{2})?/?(php)/([-a-z0-9]+)/?/?$|

Which match /php/anything.

Now I want a regular expression which match both

/php/anything
/java/anything

I tired |^(/[a-z]{2})?/?(php|java)/([-a-z0-9]+)/?/?$| but its not working.

Can someone help me with solution?
I want to keep all other part but change just (php) part.

Here is the code

preg_match("|^(/[a-z]{2})?/?(php|java)/([-a-z0-9]+)/?/?$|", 'php/anything')

But I get this warning and match doesn’t work

Warning: preg_match(): Unknown modifier 'j' 

Thanks

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T23:44:50+00:00Added an answer on June 15, 2026 at 11:44 pm

    You are using | as the regex delimiter but you have a | inside the regex as alteration, which you need to escape. If you don’t the 2nd | is treated as the end of regex and the letter following it j is treated as regex modifier. Since j is not a valid modifier, you get the error.

    You escape the | as:

    preg_match("|^(/[a-z]{2})?/?(php\|java)/([-a-z0-9]+)/?/?$|", 'php/anything')
                                    ^
    

    Or you can use a different pair of delimiter:

    preg_match("~^(/[a-z]{2})?/?(php|java)/([-a-z0-9]+)/?/?$~", 'php/anything')
                ^                                           ^
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have created a Regular Expression (using php) below; which must match ALL terms
I have a regular expression to match usernames (which functions in PHP using preg_match
I have a regular expression to match anything between { and } in my
I have written following regular expression /^[A-Za-z0-9-_\s]*$/ in PHP which allows numbers, letters, spaces,
I want to match a date-format in PHP using a regular expression. To keep
I have the simple regular expression: \{[0-9]*\} which works fine with PHP's ereg_ functions
im new to regular expressions in php. I have some data in which some
I am trying to fix a regular expression i have been using in php
I have a regular expression which allows the value range '1111' - '999999', excluding
I have a regular expression which uses GroupCollection s in it's capture to capture

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.