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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:51:22+00:00 2026-05-16T01:51:22+00:00

I have a regular expression that searches for the special characters. When I do

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I have a regular expression that searches for the special characters.

When I do a search on numerics, e.g. 3, I always get 0, when I’d expect to get -1.

'3'.search(/[!\"£\$%\^&\*\(\)-_\+=\[\]\{\};:@\'#\\|<,\.>\/\?]/)

Any idea why is this happening?

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:51:23+00:00Added an answer on May 16, 2026 at 1:51 am
    \)-_
    

    This causes the character class to include all characters between ) and _, i.e. )*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_. 3 is in one of these.

    The - should be placed at the beginning or end, so that it won’t be counted as a special character. Also, besides \, [, ] and /, there’s no need to escape anything in a character class.

    /[-!"£$%^&*()_+=\[\]{};:@'#\\|<,.>\/?]/
    

    (Technically the [ doesn’t need to be escaped either, but for consistency I prefer to escape it. Also, you could match a - in the middle if you escape it \-.)

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