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Home/ Questions/Q 505285
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:34:59+00:00 2026-05-13T06:34:59+00:00

i have a regular html Grid and i am binding my asp.net mvc view

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i have a regular html Grid and i am binding my asp.net mvc view to a strongly typed array called MyObject[]. MyObject has 40 properties but i only populate 10 of them because that is what is shown on the main grid. this is in the index view.

i want to add a column to my grid to have a link that says “Edit Details”. this would bring up jquery ui dialog with a form to fill out and allow the user to edit the details. i basically want to show my whole edit view inside the jquery ui dialog on top of the index page.

the one issue that i have is there is a lot more data in the details screen than i have brought down from the server. This was fine when Edit was a seperate page because i went back to the server and populated all the detail data and then did the binding the the edit page but i obviously can’t do that now.

So, is there anyway to rebind to a particular MyObject that I repopulate from the server or do i have to bring everything down at first and use jquery to populate these fields when i click on the row.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:34:59+00:00Added an answer on May 13, 2026 at 6:34 am

    Why not do a partial post back using jQuery to get the model you want to edit? then you can return either the model or a RenderParttial and simply display the generated html in the dialog.

    if you need samples let me know.

    EDIT

    $.post("/Controller/jQueryMethod", { param: paramValue }, function(newCommentListHTML) {
      //do something interesting with the html
    });
    

    The above will do a jquery post back to your controller and an action called jQueryMethod.

    It also passes a single parameter. Comma seperate these if you want more.

    Your controller then grabs the model and it can then pass the model to a PartialView which it then returns.

    Much like this return RenderPartial("PartialView", model);

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