I have a RelativeLayout completely created within java, not using xml layout.
I have a few buttons on the left if my screen. I want to click on one button and show a default image from my res/drawable next to the button and make it disappear again on second click.
What I have tried was toggling the visibility but my onClick() raises a FATAL EXCEPTION, NullPointer Exception.
This is my code so far. Hardcoded the image shows right when I set picview.setVisibility(View.INVISIBLE); by hand. What I am doing wrong in the onClick() ?
private ImageView picview;
//*snip* loads of other code
//Show Image Button
ImageButton show_pic = new ImageButton(this);
show_pic.setBackgroundColor(Color.WHITE);
show_pic.setOnClickListener(new OnClickListener()
{
@Override
public void onClick(View v) {
if(picview.getVisibility() == View.INVISIBLE)
{
picview.setVisibility(View.VISIBLE);
}
else if (picview.getVisibility() == View.VISIBLE)
{
picview.setVisibility(View.INVISIBLE);
}
}
});
params = new RelativeLayout.LayoutParams(40, 40);
params.topMargin = 10;
params.leftMargin = 10;
params.addRule(RelativeLayout.BELOW, button2_id);
rl.addView(show_pic, params);
//Imageview loaded from drawable
ImageView picview = new ImageView(this);
params = new RelativeLayout.LayoutParams(200, 400);
params.topMargin = 0;
params.leftMargin = 30;
params.addRule(RelativeLayout.RIGHT_OF, button2_id);
picview.setImageResource(R.drawable.my_image);
picview.setVisibility(View.INVISIBLE);
rl.addView(picview, params);
this.setContentView(rl);
You are accidentally creating two copies of
picview. Shorten this line:To:
(Your field variable
private ImageView picview;never changed fromnull, so when you clicked your Button you see the NullPointerException…)