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Home/ Questions/Q 1020915
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T11:13:55+00:00 2026-05-16T11:13:55+00:00

I have a relatively large csv/text data file (33mb) that I need to do

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I have a relatively large csv/text data file (33mb) that I need to do a global search and replace the delimiting character on. (The reason is that there doesn’t seem to be a way to get SQLServer to escape/handle double quotes in the data during a table export, but that’s another story…)

I successfully accomplished a Textmate search and replace on a smaller file, but it’s choking on this larger file.

It seems like command line grep may be the answer, but I can’t quite grasp the syntax, ala:

grep -rl OLDSTRING . | xargs perl -pi~ -e ‘s/OLDSTRING/NEWSTRING/’

So in my case I’m searching for the ‘^’ (caret) character and replacing with ‘”‘ (double-quote).

grep -rl " grep_test.txt | xargs perl -pi~ -e 's/"/^'

That doesn’t work and I’m assuming it has to do with the escaping of the doublequote or something, but I’m pretty lost. Help anyone?

(I suppose if anyone knows how to get SQLServer2005 to handle double quotes in a text column during export to csv, that’d really solve the core issue.)

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  1. Editorial Team
    Editorial Team
    2026-05-16T11:13:56+00:00Added an answer on May 16, 2026 at 11:13 am

    Your perl substitution seems to be wrong. Try:

    grep -rl \" . | xargs perl -pi~ -e 's/\^/"/g'
    

    Explanation:

    grep : command to find matches
    -r : to recursively search
    -l : to print only the file names where match is found
    \" : we need to escape " as its a shell meta char
    . : do the search in current working dir
    perl : used here to do the inplace replacement
    -i~ : to do the replacement inplace and create a backup file with extension ~
    -p : to print each line after replacement
    -e : one line program
    \^ : we need to escape caret as its a regex meta char to mean start anchor
    
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