I have a remote bare repository with two branches ‘master’ and ‘testing’, where HEAD refers to ‘testing’.
When cloning this repository git checks out ‘master’, if ‘master’ and ‘testing’ are on the same revision (i.e. HEAD == testing == master).
Only if ‘testing’ is one (or more) commit(s) behind or ahead, git clone checks out the ‘testing’ branch on the local side.
I tried this with git 1.7.5 on Mac OS X (10.6.8).
Addendum:
I just tried the same with a non-bare repository:
mkdir A
cd A
git init
touch a
git add a
git commit -m "init repo A with a"
git checkout -b testing
now back in the root dir:
cd ..
git clone A B
cd B
git branch -v -a
* master 28f599b init A
remotes/origin/HEAD -> origin/master
remotes/origin/master 28f599b init A
remotes/origin/testing 28f599b init A
it’s ‘master’! Back to repo A (we are still in branch ‘testing’):
cd ../A
touch b
git add b
git commit -m "add b in branch testing"
now ‘testing’ is one commit ahead ‘master’. Now let’s clone A again:
cd ..
git clone A C
cd C
git branch -a -v
* testing 23bca39 add b in branch testing
remotes/origin/HEAD -> origin/testing
remotes/origin/master 28f599b init A
remotes/origin/testing 23bca39 add b in branch testing
You can re-verify this weird behavior by going back to A, checkout ‘master’ and merge it with ‘testing’ (so that all branches have the same head). Now clone A into D and D will be checked out on master!
Got an answer from the git mailing list – @Shelhamer: you’re right