Question

I have a requirement to combine 4 xml files into one. They are like follows.
Document 1

<doc1>
....
<doc1>

Document 2

<doc2>
....
<doc2>

Document 3

<doc3>
....
<doc3>

Document 4

<doc4>
....
<doc4>

I want the output as follows

<doc1>
....

<doc2>
....
</doc2>


<doc3>
....
</doc3>


<doc4>
....
</doc4>
</doc1>

I did it as follows.

<xsl:transform version="2.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="/">
      <xsl:copy-of select="document('doc1.xml')"/>
      <xsl:copy-of select="document('doc2.xml')"/>
      <xsl:copy-of select="document('doc3.xml')"/>
      <xsl:copy-of select="document('doc4.xml')"/>
  </xsl:template>
</xsl:transform>

but the ouput I get is as follows

<doc1>
....
</doc1>


<doc2>
....
</doc2>


<doc3>
....
</doc3>


<doc4>
....
</doc4>

Is it possible to change my script and get what I want?

Answer 1

This transformation produces the wanted result:

<xsl:transform version="1.0"
      xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
      <xsl:template match="/">
          <xsl:for-each select="document('doc1.xml')/*">
            <xsl:copy>
             <xsl:copy-of select="@*|node()"/>

             <xsl:copy-of select="document('doc2.xml')"/>
             <xsl:copy-of select="document('doc3.xml')"/>
             <xsl:copy-of select="document('doc4.xml')"/>
            </xsl:copy>
          </xsl:for-each>
      </xsl:template>
</xsl:transform>