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Home/ Questions/Q 7953435
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T03:09:32+00:00 2026-06-04T03:09:32+00:00

I have a sample code html: $text = ‘<img src=abc.jpg alt=abc /> abc def

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I have a sample code html:

$text = '<img src="abc.jpg" alt="abc" /> abc def ghi abc xyz';
echo str_replace('abc', 'has replace', $text);

when i echo result is in tag <img/> has replace ‘abc‘ to ‘has replace‘ => error

How to when run result is:

<img src="abc.jpg" alt="abc" /> has replace def ghi has replace xyz
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T03:09:33+00:00Added an answer on June 4, 2026 at 3:09 am

    I have a ideas:

    $k=0;
    $arr = array();
    $regex = '/(<img.*?\/>)/ism';
    if(preg_match_all($regex, $text, $tmp)) {
       if(isset($tmp[0])) {             
          for($i = 0;$i < count($tmp[0]); $i++) {
             $arr[0][$k] = $tmp[0][$i];
             $arr[1][$k] = md5($tmp[0][$i]);
             $text = str_replace($arr[0][$k], $arr[1][$k], $text);
             $k++;
          }
       }
    }
    

    And then you can replace:

    echo str_replace('abc', 'has replace', $text); 
    

    Result now is:
    $text = ’74d3ae3af91872413da1db45d88ddd4a abc def ghi abc xyz’; // img has been md5

    Final you can:

    for($i = 0;$i < $k; $i++) {
        $text   = str_replace($arr[1][$i], $arr[0][$i], $text);
    }
    

    Hope you will successful

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