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Editorial Team
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Asked: 2026-06-14T14:45:42+00:00

I have a scala process command like below to use linux bash egrep command.

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I have a scala process command like below to use linux bash egrep command. But the search results are not the same in terminal and in my scala generated file. Scala results contain everything that has “new” and “Exception” while I want the output to contains only lines having “new Exception”. Am I missing something here? Please help

    if (("egrep -r -I -n -E \"*new Exception*\" /mysource/" #| 
            "grep -v .svn").! == 0) {
        out.println(("egrep -r -I -n -E \"*new Exception*\" /mysource/" #| 
            "grep -v .svn").!!)
    }
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1 Answer

  1. Editorial Team

    The docs say (under “What to Run and How”): Implicitly, each process is created either out of a String, with arguments separated by spaces -- no escaping of spaces is possible -- or out of a scala.collection.Seq, where the first element represents the command name, and the remaining elements are arguments to it. In this latter case, arguments may contain spaces

    So, apparently if you need to pass the command line a single argument with spaces, like new Exception, you need to create the process builder from a Seq instead of a single String.

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