Question

I have a script called a.sh, contents of which are:

//a.sh:

#!/bin/bash
temp=0
while [ "$temp" -ne 500 ]
do
    echo `date`
    temp=`echo "$temp+1" | bc`
    sleep 1
done
----------------------------------

Another script namedb.sh, contents of which are:

// b.sh:

#!/bin/bash

`a.sh`

exit
----------------------------------

When i execute a.sh separately, i’m able to see the output.. but, when i execute b.sh, i’m not able to see the output on the console.. (i tried a few times – to redirect the output of a.sh – but not being successful).

So, what i need is the redirection, which will enable me to see the output of a.sh‘s contents when i execute b.sh – on the console.

Thanks,
Ravi.

Answer 1

`a.sh`

in your b.sh means take the output of a.sh and use it as a command with arguments. you just have to execute a.sh in b.sh

$A_SH_PATH/a.sh instead of

`a.sh`