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Home/ Questions/Q 9215839
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T02:17:33+00:00 2026-06-18T02:17:33+00:00

I have a script here: http://jsfiddle.net/d2rcx/ It has an array of badWords to compare

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I have a script here:

http://jsfiddle.net/d2rcx/

It has an array of badWords to compare input strings with.

This script works fine if the input string matches exactly as the swear word string but it does not pick up any variations where there is more characters in the string e.g. whitespace before the swear word.

Using this site as reference : http://www.zytrax.com/tech/web/regex.htm

It said the following regex would detect a string within a string.

var regex = new RegExp("/" + badWords[i] + "/g");
        if (fieldValue.match(regex) == true)
            return true;    

However that does not seem to be the case.

What do I need to change to the regex to make it work.

Thanks

Also any good links to explain Regex than what google turns up would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-18T02:17:34+00:00Added an answer on June 18, 2026 at 2:17 am

    Here’s a corrected JSFiddle:

    http://jsfiddle.net/d2rcx/5/

    See the following documentation for RegExp:

    https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/RegExp

    Note that the second parameter is where you should specify your flags (e.g. ‘g’ or ‘i’). For example:

    new RegExp(badWords[i], 'gi');
    
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