Question

I have a script that gets the input from the user as an absolute path (using the fselect dialog box).

backupdir=$(user_select "choose a directory backup destination");

I used

tar cvzf backup.tar.gz $backupdir

however this includes the absolute directory path (*1) so instead I attempted (out-with the script):

tar czvf backup.tar.gz -C $PATH directory-to-backup

Therefore, in my script I can use:

pathtodir = dirname $backupdir 

to get the $PATH of the backup directory but I need the name of the directory I wish to backup i.e:

dirname = ..
tar czvf backup.tar.gz -C $PATH $dirname

How do I get the name of $dirname?

_{1 – “Removing leading `/’ from member name”}

Answer 1

Okay, to be honest I had some difficulty to figure out the question at first. I think we sorted that in the comments.

So you have $backupdir which contains the absolute path to the backup directory, plus $pathtodir which is a parent directory of the backup directory.

You can now use string substitution in Bash as follows:

# Replace $pathtodir with empty string inside $backupdir
relativepath=${backupdir//$pathtodir/}
# Now remove the leading slash, if any
relativepath=${relativepath#/}

If I misunderstood something still, let me know and I’ll adjust the answer accordingly.