Question

i have a script which takes data from a database and displays it on a page.

It sorts the rows by an id number, and displays them in that order

heres the script

// get the info from the db 
$sql = "SELECT showtime, html FROM showfeed ORDER BY showtime ASC LIMIT $offset, $rowsperpage";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);

// while there are rows to be fetched...
while ($list = mysql_fetch_assoc($result))
{ 
   // echo data
   echo $list['html'] . "<hr />";
} // end while

what I want to do is filter that data so that if the ID number of a row is less than a given number than it won’t be displayed. And if it is greater than a certain number it will be displayed normally.

Answer 1

Assuming ID is a field in your table:

$sql = "SELECT id, showtime, html FROM showfeed ORDER BY showtime ASC LIMIT $offset, $rowsperpage";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);

// while there are rows to be fetched...
$targetID = 120;
while ($list = mysql_fetch_assoc($result))
{ 
   // echo data
   if ($list['id'] < $targetID) continue;
   echo $list['html'] . "<hr />";
} // end while

However, if this would work for you, then probably better to change your query to

$sql = "SELECT showtime, html FROM showfeed WHERE id > 120 ORDER BY showtime ASC LIMIT $offset, $rowsperpage";