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Home/ Questions/Q 6373429
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:21:48+00:00 2026-05-25T01:21:48+00:00

I have a search Api I’m working on that needs to return search results

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I have a search Api I’m working on that needs to return search results in a block of Html (using styles the client has defined on their end). I would also like to return results in Json, for future Api stuff we’ll eventually be using. Currently, the routes look like this:

/api/1/search/json?param1=blah&param2=blah&etc
/api/1/search/html?param1=blah&param2=blah&etc

For reference, the pattern here is /{area}/1/{controller}/{action}.

I like the look of some Api’s I’ve seen that return results in different formats depending on the ‘extension’ they have in the url, a la:

/api/1/search.json?param1=blah&param2=blah&etc

However, I haven’t figured out how to configure Asp.Net’s Mvc routing to support this style. The general routing in ApiAreaRegistration.cs is:

context.MapRoute(
    "Api_default",
    "Api/1/{controller}/{action}/{id}",
    new { action = "Index", id = UrlParameter.Optional });

I have tried the following, defined above the general one, which doesn’t work:

//search api
context.MapRoute(
    "searchJson",
    "api/1/{controller}.{action}",
    new { controller = "SearchController" });

How would I configure routing to enable the .format-style urls?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:21:49+00:00Added an answer on May 25, 2026 at 1:21 am
    context.MapRoute(
        "Api_default",
        "{area}/1/{controller}.{format}",
        new { action = "Index", id = UrlParameter.Optional });
    

    is probably what you want. Then you could just return the different results based on the argument passed in.

    Within the context of an Api Area, the SearchController would look like this:

    public class SearchController : Controller
    {
        public ActionResult Index(string format, SearchModel search)
        {
            var results = searchFacade.SearchStuff(search);
    
            if(format.Equals("xml"))
                return Xml(results); //using an XmlResult or whatever
            if(format.Equals("html"))
                return View(results);
            return Json(results, JsonRequestBehavior.AllowGet);
        }
    }
    
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