I have a search script that retrieves an integer from one table and uses it to search through the IDs of a 2nd table. My issue is if the integer in Table1 appears more then once, I get duplicate results when querying Table2.
Does anyone know a way to use SQL or PHP so that if a row is already displayed it will skip it? Thanks
My code is rather convuleted but here it is if it helps:
//TV FILTERS
$sql = 'SELECT * FROM `table1`';
$where = array();
if ($searchlocation !== 'Any') $where[] = '`value` LIKE "%'.$searchlocation.'%"';
if ($searchmake !== 'Any') $where[] = '`value` LIKE "%'.$searchmake.'%"';
if ($searchtype !== 'Any') $where[] = '`value` LIKE "%'.$searchtype.'%"';
if (count($where) > 0) {
$sql .= ' WHERE '.implode(' OR ', $where);
} else {
// Error out; must specify at least one!
}
$tvqresult = mysql_query($sql);
$num_rowstvq = mysql_num_rows($tvqresult);
while ($rowtvq = mysql_fetch_array($tvqresult)) {
$contid = $rowtvq['contentid'];
//MAIN QUERY
$mainsql = 'SELECT * FROM `table2` WHERE `content` LIKE "%' . $searchterm . '%" AND `id` = ' . $rowtvq['contentid'] . ' AND `template` = 12';
$resultmain = mysql_query($mainsql);
$num_rowsmain = mysql_num_rows($resultmain);
if (!$resultmain) {
continue;
}
else {
while ($row = mysql_fetch_array($resultmain )) {
echo "[!Ditto? &parents=`134` &documents=" . $row['id'] . "&tpl=`usedtempchunk`!]";
}//END MAIN LOOP
}//END MAIN ELSE
}//END TV WHILE LOOP
You only seem to use the
contentidcolumn from your first query, so you could change it to:which would mean that no duplicates will be retreived saving you any hassle in changing your second set of code.
If you are using other columns from the first query somewhere else in your code, you can still fetch more columns with this method as long as there are no duplicate IDs:
If you have to have repeated IDs in your original query, I think you will have to store the data in a variable (like an array) and then make sure that the second dataset isn’t repeating anything.