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Home/ Questions/Q 892407
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T14:02:59+00:00 2026-05-15T14:02:59+00:00

i have a select box where in it has a list of items and

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i have a select box where in it has a list of items and he enters value for each selected option and saves it .
i have written a function like.

$('.add_recordings').click(function () {
    if (($('#recordings_name').val() != '') && ($('#recordings_value').val() != '')) {
        if ($('#recordings').val() == '') {
            var result = $('#recordings_name').val() + '=' + $('#recordings_value').val();
            $('#recordings').html(result);

            var result1 = $('#recordings_name').val() + '=>' + $('#recordings_value').val();
            $('#recordings_array').val(result1);
        }
        else {
            var result = ', ' + $('#recordings_name').val() + '=' + $('#recordings_value').val();
            $('#recordings').append(result);

            var result1 = ', ' + $('#recordings_name').val() + '=>' + $('#recordings_value').val();
            alert(result1);
            $('#recordings_array').append(result1);
        }
    }

});

the append function for recordings_array is not working, its a input of type text.

what i am trying to do is to build an php array using jquery ,so that it can be passed in $_POST.. is there any better method to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-15T14:03:00+00:00Added an answer on May 15, 2026 at 2:03 pm

    the append function for recordings_array is not working, its a
    input of type text
    .

    why not set its value instead of appending?

    $('#recordings_array').val(result1);
    

    Edit

    if you want to append value, it’s easy on jQuery 1.4

    $('#recordings_array').val(function(i,val){
        return val + result1; 
        // this will get the current value of the input (val), 
        // add result1, then return the result as the new value of the input
    });
    

    below jQuery 1.4

    $('#recordings_array').val($('#recordings_array').val() + result1);
    
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