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Editorial Team
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Asked: 2026-06-02T02:12:00+00:00

I have a select box where the user chooses a sex (gender) from a

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I have a select box where the user chooses a sex (gender) from a drop down, and their choice is specified with “selected” in the select tag. But the box always ends up ‘Choose’. What is wrong in the following syntax?

echo"<select name='sex'>
<option value='N' '". ($info['sex'] == "N" ? 'selected=selected':'') ."'>Choose</option>
<option value='M' '". ($info['sex'] == "M" ? 'selected=selected':'') ."'>Male</option>    
<option value='F' '". ($info['sex'] == "F" ? 'selected=selected':'') ."'>Female</option> 
</select>";

The $info['sex'] is from a consult SQL that return always N, M or F.

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1 Answer

  1. Editorial Team

    Your selected=selected is being quoted and output like 

    <option value='N' 'selected=selected'>

    when you run your code, use this

    echo"<select name='sex'>
<option value='N' ". ($info['sex'] == "N" ? 'selected=\'selected\'':'') .">Choose</option>
<option value='M' ". ($info['sex'] == "M" ? 'selected=\'selected\'':'') .">Male</option>    
<option value='F' ". ($info['sex'] == "F" ? 'selected=\'selected\'':'') .">Female</option> 
</select>";

    notice the escaped quotes at 'selected=\'selected\'' and the lack of single-quotes at ". ($info['sex'] and .">

    demo: http://codepad.org/AX95BzTR

    here’s a fiddle showing your problematic output: http://jsfiddle.net/JKirchartz/KB4rv

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