Question

I have a select statement and want to return all values only if at least one of them has a date with 60 days of difference from today.
The problem is that i have an outer apply which returns the column i want to compare to, and they come from different tables (one belongs to cash items, and the other to card items).
Considering I have the following:

OUTER APPLY (
    SELECT COUNT(*) AS quantity, MIN(date) AS item_date
        FROM dbo.get_cash_items(loans.id_cash) AS cash_item
        HAVING loans.id_product_type = 1 --Cash
    UNION
    SELECT COUNT(*) AS quantity, MIN(date) AS item_date
        FROM dbo.get_card_items(loans.id_card) AS card_item
        HAVING loans.id_product_type = 2 --Card
) AS items

I want to return all the rows only when DATEDIFF(DAY, MIN(items.item_date), GETDATE()) >= 60, but I want them all even if only one matches this condition.
What would be the best approach to do this?

EDIT
To make it clearer, I’ll explain the use case:
I need to show the items of every loan, only if the client is late for more than 60 days of the due date on any of it

Answer 1

I am also not sure, what do you expect, but how about that:

WITH items
     AS (SELECT Count(*)  AS quantity,
                Min(date) AS item_date
         FROM   dbo.Get_cash_items(loans.id_cash) AS cash_item
         HAVING loans.id_product_type = 1
         UNION
         SELECT Count(*)  AS quantity,
                Min(date) AS item_date
         FROM   dbo.Get_card_items(loans.id_card) AS card_item
         HAVING loans.id_product_type = 2)
SELECT a.*
FROM   items AS a,
       (SELECT TOP 1 *
        FROM   items AS b
        WHERE  Datediff(day, b.item_date, Getdate()) >= 60) AS c  

It’s a sort of CROSS JOIN, where table C will have one or zero rows depending on that if the condition is met – it will than join to every row in other table.