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Home/ Questions/Q 7574543
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T16:27:39+00:00 2026-05-30T16:27:39+00:00

I have a sequaance generator <id name=idPersistent type=objectID column=aa_id> <generator class=sequence> <param name=sequence>lab_seq</param> </generator>

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I have a sequaance generator

<id name="idPersistent" type="objectID" column="aa_id">
         <generator class="sequence">
            <param name="sequence">lab_seq</param>
         </generator>
      </id>  

objectID is my own UserType.
I got error

 javax.persistence.PersistenceException: org.hibernate.id.IdentifierGenerationException: this id generator generates long, integer, short or string

What can I do?

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  1. Editorial Team
    Editorial Team
    2026-05-30T16:27:40+00:00Added an answer on May 30, 2026 at 4:27 pm

    try these links, I hope these will help you

    • ID Generator bug in JPA implementation
    • Hibernate – Many-To-Many Example – Join Table + Extra Column (Annotation)
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