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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T20:14:41+00:00 2026-06-14T20:14:41+00:00

I have a serial no contain both characters and numbers, something like ‘ A1B2000C

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I have a serial no contain both characters and numbers, something like ‘A1B2000C‘, I want to generate next serial no by increasing number part +1. The next serial no will be A1B2001C. Is there any way to archieve it?

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  1. Editorial Team
    Editorial Team
    2026-06-14T20:14:41+00:00Added an answer on June 14, 2026 at 8:14 pm

    Not in one line, but…

    String input = "A1B2000C";
    String number = input.replaceAll(".*(?<=\\D)(\\d+)\\D*", "$1");
    int next = Integer.parseInt(number);
    next++;
    String ouput = input.replaceAll("(.*)(?<=\\D)\\d+(\\D*)", "$1" + next + "$2");
    System.out.println(ouput);
    

    output:

    A1B2001C
    

    Actually, it can be done in one line!

    String ouput = input.replaceAll("(.*)\\d+(\\D*)", "$1" + (Integer.parseInt(input.replaceAll(".*(\\d+)\\D*", "$1") + 1) "$2");
    

    But legibility suffers

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