Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6381311
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T02:22:46+00:00 2026-05-25T02:22:46+00:00

I have a series of strings stored in a single array, separated by nulls

  • 0

I have a series of strings stored in a single array, separated by nulls (for example [‘f’, ‘o’, ‘o’, ‘\0’, ‘b’, ‘a’, ‘r’, ‘\0’…]), and I need to split this into a std::vector<std::string> or similar.

I could just write a 10-line loop to do this using std::find or strlen (in fact I just did), but I’m wondering if there is a simpler/more elegant way to do it, for example some STL algorithm I’ve overlooked, which can be coaxed into doing this.

It is a fairly simple task, and it wouldn’t surprise me if there’s some clever STL trickery that can be applied to make it even simpler.

Any takers?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T02:22:46+00:00Added an answer on May 25, 2026 at 2:22 am

    My two cents :

    const char* p = str;
    std::vector<std::string> vector;
    
    do {
      vector.push_back(std::string(p));
      p += vector.back().size() + 1;
    } while ( // whatever condition applies );
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Sorry if the title doesn't make sense. Basically I have a series of strings
I have a series of date strings in the format: 30-05-2001 string date1 =
I have a series of strings that come in, that are essentially dollar values,
I need to create a structure or series of strings that are fixed lenght
I have a series of parameters stored in rows in the database, and I'd
I have a series of times that are coming to me as strings from
I have a class that collects a series of strings (contact's names) and I
I have a series of strings representing the following file names: hello1(eng).txt , hello1(por).txt
I have a series of regular expressions that include escape characters that I need
I have a series of strings, which are two numbers: 1.782-100.799 -18.107-102.016 -17.504104.059 How

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.