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Home/ Questions/Q 6057697
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:31:01+00:00 2026-05-23T08:31:01+00:00

I have a ServiceLocator shown below public class ServiceLocator { private static ServiceLocator serviceLocator

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I have a ServiceLocator shown below

public class ServiceLocator {
    private static ServiceLocator serviceLocator = null;
    InitialContext context = null;
    HashMap serviceCache = null;

    public ServiceLocator() throws NamingException {
        context = new InitialContext();
        serviceCache = new HashMap(5);
    }

    public synchronized static ServiceLocator getInstance()
            throws NamingException {
        if (serviceLocator == null) {
            serviceLocator = new ServiceLocator();
        }
        return serviceLocator;
    }

    public Object getService(String jndiName) throws NamingException {
        if (!serviceCache.containsKey(jndiName)) {
            serviceCache.put(jndiName, context.lookup(jndiName));
        }
        return serviceCache.get(jndiName);
    }
}

Could anybody tell me why does we need to store JNDI name in this way ??

serviceCache.put(jndiName, context.lookup(jndiName));
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  1. Editorial Team
    Editorial Team
    2026-05-23T08:31:02+00:00Added an answer on May 23, 2026 at 8:31 am

    Who says you need to do that? It’s just caching the results of the JNDI lookup. Under certain circumstances, JNDI lookups can be slow, so caching them may be a good idea.

    I’d find out if you really need to do this, though. The JNDI lookups may be fast enough on their own. If so, then take the serviceCache out.

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