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Home/ Questions/Q 684469
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:49:13+00:00 2026-05-14T01:49:13+00:00

I have a set of shared pointers: std::set<boost::shared_ptr<T>> set; And a pointer: T* p;

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I have a set of shared pointers:

std::set<boost::shared_ptr<T>> set;

And a pointer:

T* p;

I would like to efficiently remove the element of set equal to p, but I can’t do this with any of the members of set, or any of the standard algorithms, since T* is a completely different type to boost::shared_ptr<T>.

A few approaches I can think of are:

  • somehow constructing a new shared_ptr from the pointer that won’t take ownership of the pointed to memory (ideal solution, but I can’t see how to do this)
  • wrapping / re-implementing shared_ptr so that I can do the above
  • just doing my own binary search over the set
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:49:14+00:00Added an answer on May 14, 2026 at 1:49 am

    Construct a shared_ptr<T> from T with a null_deleter (see boost:::shared_ptr FAQ).

    struct null_deleter {
        void operator()(void const *) const { }
    };
    
    size_t remove_ptr_from_set(std::set<boost::shared_ptr<T>> &set, X* x)
    {
        shared_ptr<X> px(x, null_deleter());
        return set.erase(px);
    }
    

    That way the types are compatible and you don’t have to worry about your temporary shared_ptr deleting any object.

    Or, as one of the comments say, if you can change T to inherit from enable_shared_from_this you could get a correct shared ptr from your object.

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