Question

I have a shell and I use pwd to show in which directory I am. but when I’m in directory that it’s a symlink it show the physical directory not the symlink

import subprocess as sub

def execv(command, path):
    p = sub.Popen(['/bin/bash', '-c', command],
                    stdout=sub.PIPE, stderr=sub.STDOUT, cwd=path)
    return p.stdout.read()[:-1]

If I have folder /home/foo/mime that it’s symlink to /usr/share/mime when I call

execv('pwd', '/home/foo/mime')

I got /usr/share/mime

My code for shell look like this:

    m = re.match(" *cd (.*)", form['command'])
    if m:
        path = m.group(1)
        if path[0] != '/':
            path = "%s/%s" % (form['path'], path)
        if os.path.exists(path):
            stdout.write(execv("pwd", path))
        else:
            stdout.write("false")
    else:
        try:
            stdout.write(execv(form['command'], form['path']))
        except OSError, e:
            stdout.write(e.args[1])

And I have client in JavaScript

(probably returning result of the command and new path as JSON will be better).

Is there a way to make pwd return path to the symlink instead of the physical directory.

Answer 1

Only the current shell knows it is using a symbolic link to access the current directory. This information is normally not passed to children processes so they only know the current directory by its real path.

Should you want this information to be known to sub-processes, you need to define a way to pass it, for example through an argument or an environment variable. Exporting PWD from the shell might just work.