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Home/ Questions/Q 8235519
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T18:50:19+00:00 2026-06-07T18:50:19+00:00

I have a short bash script to get source code’s dependency files. #!/bin/sh rule=$(cpp

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I have a short bash script to get source code’s dependency files.

#!/bin/sh
rule=$(cpp -P -w -undef -nostdinc -C -M file.cc)
rule=${rule##*:}
#echo $rule
echo ${rule//\\}

Unfortunately, it outputs ./findDep.sh: 5: ./findDep.sh: Bad substitution.
But if I uncomment echo $rule, the script will execute without any problem:

lib.h macro.inc fundamental.h lib/fs.h lib/net.h \ lib/net/fetch.h
lib.h macro.inc fundamental.h lib/fs.h lib/net.h  lib/net/fetch.h

Any one know why?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-07T18:50:21+00:00Added an answer on June 7, 2026 at 6:50 pm

    I can’t reproduce your problem here with Bash 4.2.29.

    However, did you know that read will join lines with \ newline continuations by default?

    read rule < <(cpp -P -w -undef -nostdinc -C -M file.cc)
    echo "${rule##*:}"
    

    Or, in a more sh-compatible way (I think),

    cpp -P -w -undef -nostdinc -C -M file.cc | {
        read rule
        echo "${rule##*:}"
    }
    
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