Question

I have a simple dictionary:

{"keyy":{"key": "value", "cey": "value"}, "kaye":{"key": "value"}}

That I want to encode as a “context-aware” tuple:

[("keyy","key","value"), ("keyy","cey","value"), ("kaye","key","value")]

My attempt with ValueError: too many values to unpack:

if __name__=='__main__':
    mydict={"keyy":{"key": "value", "cey": "value"}, "kaye":{"key", "value"}}
    mytuplelist=[tuple(k,v,val) for (k,v) in [(key,val) for (key,val) in mydict]]
    print mytuplelist

How would I go about creating this list of tuples?

Answer 1

using list comprehension :

mydict={"keyy":{"key": "value", "cey": "value"}, "kaye":{"key": "value"}}

mytuplelist=[(key,y,mydict[key][y]) for key in mydict for y in mydict[key]]

print (mytuplelist)

output:

[('keyy', 'cey', 'value'), ('keyy', 'key', 'value'), ('kaye', 'key', 'value')]

using Simple For-In loops:

dic={"keyy":{"key": "value", "cey": "value"}, "kaye":{"key": "value"}}
lis=[]
for x in dic:
  for y in dic[x]:
      lis.append((x,y,dic[x][y]))
print(lis)

output:

[('keyy', 'cey', 'value'), ('keyy', 'key', 'value'), ('kaye', 'key', 'value')]