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Home/ Questions/Q 3840676
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T15:33:26+00:00 2026-05-19T15:33:26+00:00

I have a simple form: <form name =Add action=Add-Results.php method=post> <label for=name class=smallfont>Name</label> <input

  • 0

I have a simple form:

<form name ="Add" action="Add-Results.php" method="post">
 <label for="name" class="smallfont">Name</label>
 <input type="text" name="name" size="30" />
 <label for="name_error" class="error">Please enter a name</label>
 <input type="image" name="submit" src="../Content/Images/login-submit.gif">
</form>

Which works fine until I add in the following jquery

$(document).ready(function()
{
 $(".error").hide();
 $("input[name=submit]").click(function() 
 {
  $(".error").hide();
  var name = $("input[name=name]").val();

  if (name == "") $("label[for=name_error]").show();

 return false;
 });

});
</script>

When I put in the jquery nothing happens when I click the submit. When I take out the jquery the form posts without a problem. Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T15:33:26+00:00Added an answer on May 19, 2026 at 3:33 pm

    Maybe you could put all the logic in a function, and on the onclick event of the button call that function, like this:

    function checkName()
    {
    var flag = true;

    $(".error").hide();
    var name = $("input[name=name]").val();
    
    if (name == "")
    {
        $("label[for=name_error]").show();
        flag = false;
    }
    
    return flag;
    

    }

    then

    <input type="image" name="submit" onClick="checkName()" src="../Content/Images/login-submit.gif">
    
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