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Home/ Questions/Q 9234697
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T06:51:01+00:00 2026-06-18T06:51:01+00:00

I have a simple function that returns a primitive sum of NSNumber s, but

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I have a simple function that returns a primitive sum of NSNumbers, but doesn’t count them if they’re -1:

- (NSInteger)total {
    return [[self obj1] integerValue] == -1 ? 0 : [[self obj1] integerValue] + 
           [[self obj2] integerValue] == -1 ? 0 : [[self obj2] integerValue] +
           [[self obj3] integerValue] == -1 ? 0 : [[self obj3] integerValue];
}

In this case total will always return 0.

But if I write it like this:

- (NSInteger)total {
    NSInteger ret = 0;
    ret += [[self obj1] integerValue] == -1 ? 0 : [[self obj1] integerValue];
    ret += [[self obj2] integerValue] == -1 ? 0 : [[self obj2] integerValue];
    ret += [[self obj3] integerValue] == -1 ? 0 : [[self obj3] integerValue];
    return ret;
}

total will return the correct value.

I don’t have a preference for writing it one way over the other, but I don’t see what’s wrong with the first way.

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  1. Editorial Team
    Editorial Team
    2026-06-18T06:51:03+00:00Added an answer on June 18, 2026 at 6:51 am

    Operator precedence. The ternary operator has the third lowest precedence in C, so the addition is evaluated before it could get to the conditional part. Use parentheses:

    return ([[self obj1] integerValue] == -1 ? 0 : [[self obj1] integerValue]) + 
           ([[self obj2] integerValue] == -1 ? 0 : [[self obj2] integerValue]) +
           ([[self obj3] integerValue] == -1 ? 0 : [[self obj3] integerValue]);
    
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