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Home/ Questions/Q 7627785
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T05:30:24+00:00 2026-05-31T05:30:24+00:00

I have a simple function, which I’m trying to turn turn into a query.

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I have a simple function, which I’m trying to turn turn into a query. The idea is to grab the number of facebook likes (which I’ve done), and pass it into a simple equation (which is ready) to work out the percentage of likes against a target number. I know that the php controling the percentage will return 0.0 at the moment – that’s fine for now 🙂 I just can’t work out how to get from the function to a variable…

Code as follows:

<?php 
function bfan() {
$pageID = 'VisitTywyn';
$info = json_decode(file_get_contents('http://graph.facebook.com/' . $pageID));
echo $info->likes;
} ?>

<?php bfan(); ?>

<?php
echo number_format(($num_amount/$num_total)*100, 1);
?>

Thanks for your help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T05:30:25+00:00Added an answer on May 31, 2026 at 5:30 am

    What you want to do is return your result so it can be passed to a variable.

    <?php 
    function bfan() {
    $pageID = 'VisitTywyn';
    $info = json_decode(file_get_contents('http://graph.facebook.com/' . $pageID));
    return $info->likes;
    } ?>
    
    <?php $something = bfan(); ?>
    
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