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Home/ Questions/Q 6560535
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:28:21+00:00 2026-05-25T13:28:21+00:00

I have a simple grammar options { language = Java; output = AST; ASTLabelType=CommonTree;

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I have a simple grammar

options {
  language = Java;
  output = AST;
  ASTLabelType=CommonTree;
}

tokens {
  DEF;
}

root
  : ID '=' NUM (',' ID '=' NUM)* -> ^(DEF ID NUM)+     
  ;

and the corresponding tree grammar:

options {
  tokenVocab=SimpleGrammar;
  ASTLabelType=CommonTree;
}

root
  : ^(DEF ID NUM)+
;

However antlr (v3.3) cannot compile this tree grammar I’m getting:

syntax error: antlr: unexpected token: +
|---> : ^(DEF ID NUM)+

Also it don’t works if I want to create it as ^(ROOT ^(DEF ID NUM)+)

I want a tree that is corresponds to this (as parse creates it as well) :

(ROOT (DEF aa 11) (DEF bb 22) (DEF cc 33))

Thus antlr is capable to generate the tree in parser but not capable to parse it with tree grammar?!

Why this happens?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:28:22+00:00Added an answer on May 25, 2026 at 1:28 pm

    In order to get (ROOT (DEF aa 11) (DEF bb 22) (DEF cc 33)) you can define the following parser rules:

    tokens {
      ROOT;
      DEF;
    }
    
    root
      : def (',' def)* -> ^(ROOT def+)
      ;
    
    def
      :  ID '=' NUM -> ^(DEF ID NUM)
      ;
    

    and then your tree grammar would contain:

    root
      :  ^(ROOT def+)
      ;
    
    def
      :  ^(DEF ID NUM)
      ;
    
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