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Home/ Questions/Q 7194597
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T20:24:16+00:00 2026-05-28T20:24:16+00:00

I have a simple mouseover event that I am trying to work on elements

  • 0

I have a simple mouseover event that I am trying to work on elements that are loaded with ajax. For example I have a div that when you mouseover hide/show another div. When I load these divs through ajax they no longer work. For example :

<div class="block">
    <div class="something">MOUSEOVER</div>
    <div class="else" style="display: none" >HI</div>
</div>

$(document).ready(function(){
    //using on hoping to catch the mouse events
    $('.block').on('mouseenter',function(){
        $(this).children('.else').fadeIn('fast');
    });
    $('.block').on('mouseleave',function(){
        $(this).children('.else').fadeOut('fast');
    });
});

This works fine straight up like this :

But when I load those elements from another page :

$j('#trigger').load( url + " .block");

The mouse events are no longer recognized. I thought this is what live, on, delegate were for. Can someone help me figure this out please.

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  1. Editorial Team
    Editorial Team
    2026-05-28T20:24:17+00:00Added an answer on May 28, 2026 at 8:24 pm

    One possibility is to change your code like:

    var myFunc = function() {
        $('.block').on('mouseenter',function(){
            $(this).children('.else').fadeIn('fast');
        });
        $('.block').on('mouseleave',function(){
            $(this).children('.else').fadeOut('fast');
        });
    }
    
    $('#trigger').load(url + " .block", function() {
        myFunc();
    });
    

    to make this functions like mouseenter or mouseleave in the loaded content possible.

    The other possibility is $.live();. Like:

    $('.block').live('mouseenter', function() {
       //here your code
    });
    
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