I have a simple mysql select query in my PHP code: $result = mysql_query(SELECT

Question

Asked: May 26, 20262026-05-26T15:07:34+00:00 2026-05-26T15:07:34+00:00

I have a simple mysql select query in my PHP code:

$result = mysql_query("SELECT text FROM example ORDER BY rank DESC");
while($row = mysql_fetch_array($result))
  {
  echo $row['text'] . "<br>";
  }

and this MySql table:

   text | rank
--------+--------
 google | 245
--------+--------
 yahoo  | 32
--------+--------
 bing   | 12

When I get the results from the query, something like this gets displayed:

yahoo 
google
bing

I want Google to be in front. I guess Yahoo is in first because it starts with “3”.

How could I make the query order the results by the size of the numbers in rank?

Thanks…

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Editorial Team · Answer 1 · 2026-05-26T15:07:34+00:00

Editorial Team

I’m guessing the rank field is some kind of string type. Make it a numeric type int and it will order properly

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