Question

I have a simple problem that says:

A password for xyz corporation is supposed to be 6 characters long and made up of a combination of letters and digits. Write a program fragment to read in a string and print out a message as to whether or not the string entered would be considered a valid password.

I need help on completing this code. I have this pseudocode that I can’t workout into Java code:

print "enter new password"
input newPassword
digitCounter =0
letterCounter = 0
for I = 0 to newPassword.length() by 1
    c = newPassword.charAt(i)
    if c is a digit
        increment digitCounter
    else if c is a letter
        increment letterCounter
    endif
endFor
if newPassword.length() >= 6 and digitCounter > 0 and letterCounter > 0
    print "the password is valid"
else
    print " password rejected, must be at least 6 characters long and be a mix of letters and digits "
endif

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

So far all I have is this for the Java code:

import java.util.Scanner;

public class Password 
{
    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);

        String thePassword;

        int len, i, letterCounter = 0, digitCounter = 0;
        char c;

        Len = thePassword.length();

        System.out.print("Enter the password: ");
        thePassword = in.nextLine();

        for (i = 0,i = len, )
        {
            c = in.charAt(1);

            if ()
        }

    }
}

Answer 1

Take a look at Character.isDigit() and Character.isLetter() for checking the characters:

If you want to use String.charAt() to get the characters of your string, you could do a for loop like so:

for (int i = 0;i < s.length();i++) {
    char c = s.charAt(i);
    //Check things about c
}

Although Java 1.5 instroduced a For-Each loop which will loop automatically over arrays like so:

for (char c : s.toCharArray()) {
    //Check things about c
}