Question

I have a simple query in PHP but I can’t get Like to work.

Here is the code:

$var = $_GET['q'];
$trimmed = trim($var);
$query = "SELECT * FROM vm_regiony WHERE nazev LIKE "%$trimmed%" order by id     LIMIT 10";
$result = mysql_query($query);
if(mysql_num_rows($result)==0){
  echo "nothing";
  echo "<br />";
  echo $trimmed;
}else{
  while($rene=mysql_fetch_array($result)){
    $jmeno = $rene['nazev'];
    echo '<a id="hled" onclick="javascript:vybrat()">'.$jmeno.'</a>';

Answer 1

For one you need to use single quotes there

$query = "SELECT * FROM vm_regiony WHERE nazev LIKE '%$trimmed%' order by id LIMIT 10";